Question 261632
The perimeter of  a rectangle is 100 meters. Its length is 7 meters less than twice its width. Find its area.


Let width be W


Then length = 2W - 7, since its length is 7 meters less than twice its width


Since its perimeter is 100 meters, and since perimeter = 2W + 2L, we will then have:


2W + 2(2W - 7) = 100


2W + 4W - 14 = 100


6W = 114


W, or width = {{{114/6 = 19}}} meters


Since its width, or W = 19, then L, or its length = 31 (2*19 - 7)


Since its width = 19, and length = 31, then its area = 19 * 31 = {{{highlight_green(589) m^2}}}, or squared meters.