<PRE><B>Question 261632</B>
The perimeter of  a rectangle is 100 meters. Its length is 7 meters less than twice its width. Find its area

Let the width be x
Twice width = 2x
Seven less than twice the width = 2x-7

Perimeter = 2*(l+w)
                   = 2*(2x-7+x)
                   = 2*(3x-7)
                  = 6x-14 =100
2x= 114
X= 57
Width =2x = 114

Area = L*w= 114 * 57=6498 square meters

M Ananth------------ mananth@hotmail.com

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