Question 261619
 "One train leaves city A heading for city B which is 390 miles away. At the same time a second train leaves city B heading for city A, Going 15 mph faster then the first train. If they meet in 3 hours and 20 minutes how fast were the trains traveling? 
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3:20 is not 3.2 hours, it's 3 1/3 hours.
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d = rt
The speeds are added since they're going opposite directions.
Train A is going x mph
Train B is going x+15 mph.
The sum is 2x+15 mph
The go 390 miles in 3 1/3 hours, so their speed is
390/(10/3) = 117 mph
2x+15 = 117
x = 51 mph, the speed of the 1st train
66 mph = the speed of the 2nd train