Question 261445
We j=have the following:
{{{a^2 + b^2 = 11}}}
{{{ab=3}}}
--
Now,
{{{(a+b)^2 = a^2 + 2ab + b^2}}}
from above, we substitute to get
{{{(a+b)^2 = 14 + 2*3}}}
or
{{{(a+b)^2 = 20}}}
--
next,
{{{a-b)^2 = a^2 - 2ab + b^2}}}
from above, we substitute to get
{{{(a-b)^2 = 14 - 2*3}}}
or
{{{(a-b)^2 = 8}}}