Question 261422
Unfortunately, that is not correct. Why? Since the quadratic goes through the point (1,3), this means that when x=1 then y=3. Plugging in x=1 gets us {{{y=(1+1)^2-5=2^2-5=4-5=-1}}} which is not what we're looking for.



What you need to do is set up the equation {{{y=a(x+1)^2-5}}}, plug in the values x=1 and y=3 and solve for 'a'.



Your answer should be {{{a=2}}} which means that the equation of the quadratic is {{{y=2(x+1)^2-5}}}. Let me know if you need help getting to that answer.