<PRE><B>Question 261167</B>
The columbia power company experiences power failures with a mean of u = 0.210 per day. find the probability that there are exactly two power failures in a particular day?
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It&#39;s a Poisson problem with mu = 0.210 and x = 2
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P(2,0.210) = [e^(-0.210)(0.210)^2]/2! = 0.01787..
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If you use a TI-84 (or better) poisson(0.210,2) = same answer
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Cheers,
Stan H.
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