Question 261294
Use left to right elimination method to solve the system
x-3y-z=0
x-2y+z=8
2x-6y+z=6

 x - 3y - z = 0 (multiply by -2 and add to the 3rd)
 x - 2y + z = 8
2x - 6y + z = 6

-2x + 6y + 2z = 0
  x - 2y +  z = 8
 0x + 0y + 3z = 6

3z=6 --> z=2

-2x + 6y + 4 = 0 --> -2x + 6y = -4
  x - 2y + 2 = 8 -->   x - 2y =  6 (multiply by 2)

-2x + 6y = -4
 2x - 4y = 12 (add 1st to 2nd)

-2x + 6y = -4
 0x + 2y = 8

2y=8 --> y=4

-2x + 6*4 = -4
-2x + 24 = -4
-2x = -28
x=14

check: x-3y-z=0  --> 14 - 3*4 - 2 = 14 - 12 - 2 = 14 - 14 = 0
       x-2y+z=8  --> 14 - 2*4 + 2 = 14 - 8 + 2 = 14 - 6 = 8
      2x-6y+z=6  --> 2*14 - 6*4 + 2 = 28 - 24 + 2 = 4 + 2 = 6