Question 261104
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We'll do one number, and take from there to solve the rest.


3){{{3y+2=x-4}}}


Let Fx=0: {{{3y+2=0-4}}}
{{{3y=-4-2}}}
{{{3y=-6}}} ---> {{{cross(3)y/cross(3)=cross(-6)2/cross(3)1}}}
{{{y=-2}}}
Point (0,-2)

Let Fy=0: {{{3(0)+2=x-4}}}
{{{2+4=x}}}
{{{x=6}}}
Point (6,0)


So the line passes thru points ({{{0}}},{{{-2}}}) & ({{{6}}},{{{0}}}):
{{{drawing(250,250,-9,9,-5,5,grid(1),graph(250,250,-9,9,-5,5,(1/3)x-2),green(circle(0,-2,.18)),green(circle(6,0,.18)))}}}


Thank you,
Jojo</font>