Question 32822
1.   3a^2=-a+2
first, let us get the whole equation equal to zero; so:
3a^2+a-2=0
then, multiply the leading coefficient(the coefficient with the variable that has the highest degree; it is 3 in this problem) with the constant (the number that doesn't have a variable; it is -2 in this problem) to get -6......
now, find factors of -6 that add up to the coefficient of the middle term (1a)
Those factors are 3 and -2....so let us fit those numbers into the problem
3a^2+a-2=0 original
3a^2+3a-2a-2=0 original with factors
(3a^2+3a)+(-2a-2)=0 grouping
3a(a+1)-2(a+1)=0 take out the common multiple
(3a-2)(a+1)=0 combine
now, use the zero property to find what (a) is:
3a-2=0
a=2/3
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a+1=0
a=-1
SO, -1 and 2/3 are your answers!
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2.   3(x-3)=2(6-x)
3(x-3)=2(6-x) original
3x-9=12-2x distribute
5x=21 get all variables to one side and vise versa with constant numbers
x=21/5 your answer!