Question 32802
{{{((x^2-6x+8)/(x^2-2x))/(3x-12)}}}

First we begin by simplifying {{{x^2-6x+8}}}
{{{X^2 -4x-2x-8 = (X-4)(X-2)}}}

Then {{{X^2- 2X}}} we take X common and we get X(X-2)

Similarly for 3X-12 we take 3 common and we get 3(X-4)

Now we know that {{{(a/b)/c = a/bc}}}

So you get 
{{{((X-4)(X-2))/X(X-2)3(X-4)}}}

Cancelling the common terms you get {{{1/3X}}} as your final answer