Question 260981
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Let *[tex \Large x] represent the number of 2 wheeled cycles.


Let *[tex \Large y] represent the number of 3 wheeled cycles.


Since the shop had 15 cycles and they are all either 2 wheeled or 3 wheeled, then:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ y\ =\ 15]


The number of wheels on *[tex \Large x] two-wheeled cycles must be *[tex \Large 2x].  The number of wheels on *[tex \Large y] three-wheeled cycles must be *[tex \Large 3y].  And the sum of the wheels is 34, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2x\ +\ 3y\ =\ 34]


Just solve the system of equations and you have your answer.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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