Question 260821
2x^2-3x=-10
2x^2-3x+10=0
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
x=(3+-sqrt[-3^2-4*2*10])/2*2
x=(3+-sqrt[9-80])/4
x=(3+-sqrt-71)/4
x=(3+-8.426i)/4
x=3/4+-8.426i/4
x=.75+-2.1i ans.