Question 32691
4y/8y+4*12y+6/7==>4y/2(4y+1)*6(2y+1)/7==>4y/4y+1*3(2y+1)/7==>4y(3)(2y+1)/7(4y+1)
12y(2y+1)/7(4y+1)==>24y^2+12y/28y+7==>12y(2y+1)/7(4y+1