Question 260767
rewrite as
{{{(p^3)^2 - (8a^3)^2}}}
this is a difference of two squares, so we factor as
{{{(p^3+8a^3)(p^3-8a^3)}}}
now we can factor each parenthesis as sum and difference of cubes as
(p^3 + 8a^3) = (p+2a)(p^2-2ap+4a^2)
and
(p^3 - 8a^3) = (p-2a)(p^2+2ap+4a^2)
so our final answer is
{{{(p+2a)(p^2-2ap+4a^2)*(p-2a)(p^2+2ap+4a^2)}}}