Question 260707
For a right isoceles triangle,
{{{x^2+x^2=12^2}}}
{{{2x^2=144}}}
{{{x^2=72}}}
{{{x=sqrt(72)=6sqrt(2)}}}
{{{P=6sqrt(2)+6sqrt(2)+12=12sqrt(2)+12}}}
or approximately
{{{P=28.97}}}
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{{{A=(1/2)bh=(1/2)x^2=36}}}