Question 260571
Complete the square in x and y.
{{{x^2+ y^2-6x+ 4y +10= 0 }}}
{{{(x^2-6x)+ (y^2+4y) +10= 0 }}}
{{{(x^2-6x+9)+ (y^2+4y+4) +10= 9+4 }}}
{{{(x-3)^2+ (y+2)^2= 3 }}}
Compare this to the general equation for a circle centered at (h,k) with a radius R is:
{{{(x-h)^2+(y-k)^2=R^2}}}
This equation is a circle centered at (3,-2) with a radius of {{{R=sqrt(3)}}}.
{{{ graph( 300, 300, -6, 6, -6, 6, -2+sqrt(3-(x-3)^2), -2-sqrt(3-(x-3)^2) )}}}