Question 260620
the product of two consecutive integers is 8 less than 8 times their sum.  find the integers.

let one number be x
then the other number will be x+1

x(x+1) is the product

x+(x+1) = sum of the numbers

8(x+x+1) = eight times their sum

8(x+x+1)- 8          (less 8)

x(x+1) = 8(x+x+1)-8 

x^2+x = 8x+8x+8-8

x^2 + x -16x= -8
x^2-15x=0
x(x-15)=0

x=0 or 15

x cannot be zero. so the numbers are 15, 16


M Ananth-------- mananth@hotmail.com