Question 260520
the length of a rectangle mailing is four centimeters less than twice the width. the perimeter is 40 centimeters. Find the dimensions of the label?

Let the width be x

twice the width = 2x

length is 4cms less than twice the width
 so length = 2x-4

Perimeter of rectangle -= 2*( length + width)
= 2 * ( x+ 2x -4)
=2*(3x-4)
= 6x-8

6x-8 = 40
6x= 40+8=48
x=8

2x-4 = width
2*8-4=12

width 8, length 12