Question 260550
 the hypotenuse of a right triangle is 26 cm. the sum of the two other sides is 34 cm. find the lengths of the other two sides of the triangle.
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let one side be x
The other side is 34-x
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Pythagoras:
x^2 + (34-x)^2 = 26^2
x^2 + 1156  - 68x + x^2 = 676
2x^2 -68x + 480 = 0
x^2 - 34x + 240 = 0
(x-24)(x-10) = 0
x = 24 or x = 10
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One side is 10 cm the other is 24 cm.
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Cheers,
stan H.