Question 260536
here is the problem
{{{log(4,2x+5)-log (4,x-2) =1}}}
step 1 - use rules of logs on the left to get
{{{log(4,((2x+5)/(x-2))) =1}}}
step 2 - rewrite as exponents like this
{{{4^1 = (2x+5)/(x-2)}}}
step 3 - cross multiply to get
{{{4x-8 = 2x+5}}}
step 4 - solve for x to get
{{{2x = 13}}}
x = 13/2