Question 260519
here is the problem
{{{log (4,2x+5)-log(4,x-2)=1}}}
step 1 - use rules of logs on the left to get
{{{log (4,((2x+5)/(x-2)))=1}}}
step 2 - rewrite as exponents like this
{{{4^1 = (2x+5)/(x-2)}}}
step 3 - cross multiply to get
{{{4x-8 = 2x+5}}}
step 4 - solve for x to get
{{{2x = 13}}}
x = 13/2