<PRE><B>Question 260522</B>
On August 28, the Corwin family recieved 27 pieces of mail, consisting of magazines, bills, letters and ads. 
m + b + L + a= 27
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If they recieved the same number of magazines as letters, three more bills than letters, and five more ads than bills, how many magazines did they recieve? Write an algebraic equation.
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m = L
b = L + 3
a = b + 5
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Substitute to get:
L + (L+3) + L + (L+3)+5 = 27
4L + 11 = 27
4L = 16
L = 4 = m (# of letters and number of magazines)
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b = L+3 ; b = 7 (# of bills)
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a = b + 5 = 12 (# of ads)
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Cheers,
Stan H.

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