Question 260512
here is the original problem
{{{10-log(5,2x-9)=9}}}
step 1 - subtract 10 to get
{{{-log(5,2x-9) = -1}}}
divide by -1 to get
{{{log(5,2x-9) = 1}}}
rewrite as powers to get
 {{{5^1 = 2x-9}}}
solve for x to get
{{{x = 7}}}