Question 260516
Here is the question
{{{log(3x)= log 5 + log(x-2)}}}
step 1 subtract log(x-2) to get
{{{log(3x) - log(x-2) = log(5)}}}
step 2 - rewrite using rules of logs as
{{{log(3x/(x-2)) = log(5)}}}
step 3 - eliminate logs to get
{{{3x/(x-2) = 5}}}
step 4 - cross multiply to get
{{{3x = 5x - 10}}}
solve for x and we get
x = 5