Question 260483
Let A be the first number and B be the second number
three times one number equals twice a second number
 translates as
(i) {{{3A = 2B}}}
twice the first number is 3 more than the second number
translates as
(ii) {{{2A = B + 3}}}
solve (ii) for B to get
(iii) {{{B = 2A - 3}}}
substitute (ii) into (i) to get
(iv) {{{3A = 2(2A-3)}}}
distribute to get
(v) {{{3A = 4A - 6}}}
subtract 4A to get
(vi) {{{-A = -6}}}
divide by -1 to get
(vii) {{{A = 6}}}
since A = 6, {{{B = 9}}}