Question 32728
3^(2x+2) = 7^X
ln (3^2x+2) =ln 7^x
(2x+2) ln (3) = x ln(7)
2x ln (3)-x ln 7 = -2 ln 3
x[2 ln (3) - ln (7)] = -2 ln(3)
x = [2 ln (3) - ln (7) ]/ [-2 ln(3)]

x= ln (7)/[2 ln (3)] - 1