Question 260421

(x^2+3x-54)/ (x+9) 

{{{(x^2+3x-54)/(x+9)}}}
You might guess that you can factor the numerator into (x+9) and something else.

9 and what makes 54
9 and 6
but we want 3x not 15 x
so either 9 or 6 must be negative.
but if 9 is negative then we would have -3x
so it must be(x-6)(x+9)/(x+9) and that reduces to x-6
x-6 is the answer
*[invoke change_this_name4450 1, 3, -54, "x"]