Question 260357
The ratio of Aldo's cycling speed to Jose cycling speed is 6:5.
 Jose leaves school at 3pm and Aldo leaves at 3:10pm.
 By 3:30pm Aldo is only 2km behind Jose. How fast is each cycling?
:
Let x = the multiplier
then
6x = A's speed
and
5x = J's speed
:
At 3:30
30 min = J's travel time, which is {{{1/2}}} hr
20 min = A's travel time, which is {{{1/3}}} hr
:
Write a distance equation: Dist = speed * time
:
J's dist - A's dist = 2 km
{{{1/2}}}(5x) - {{{1/3}}}(6x) = 2
Multiply equation by 6 to get rid of the denominators, results
3(5x) - 2(6x) = 6(2)
:
15x - 12x = 12
:
3x = 12
x = {{{12/3}}}
x = 4 is the multiplier
:
6*4 = 24 km/hr is A's speed
5*4 = 20 km/hr is J's speed
:
:
Check solution by finding the distance each traveled
A:{{{1/3}}} * 24 = 8 km
J:{{{1/2}}} * 20 = 10 km; 2km difference