Question 32695
[3/(y^2-3y+2)] + 7/(y^2-1)
= [3/(y-2)(y-1)] + 7/(y-1)(y+1)
= [3(y+1) + 7(y-2)]/(y-1)(y+1)(y-2)
= (10y-11)/(y-1)(y+1)(y-2)