Question 260329
To factor trinomials of this form:
step 1 - factor out the a from the first two terms to get
 {{{a(x^2 + (b/a)x) + c}}}
step 2 - take 1/2 of the middle term and square it. We get
{{{a(x^2 + (b/a)x + (b/2a)^2) + c}}}
step 3 - place a blank slot after c and we get
{{{a(x^2 + (b/a)x + (b/2a)^2) + c - _____ }}}
this blank slot is waiting for a number.
step 4 - multiply (b/2a)^2 by a and put that answer in the blank slot to get
{{{a(x^2 + (b/a)x + (b/2a)^2) + c - b^2/(4a)}}}
step 5 rewrite the trinomial as a binomial squared as
{{{a(x+(b/(2a)))^2 + (4ac-b^2)/(4a)}}}
we have our factored form for x.