Question 260322
We really have two coordinates here as:
(50,30) and (80,50)
we can find slope as
{{{m = (y2-y1)/(x2-x1)}}}
putting our numbers in, we get
{{{m = (50-30)/(80-50)}}}
{{{m = 20/30}}}
or
{{{m = 2/3}}}
using a coordinate and our slope we can find the b value as
{{{y = mx + b}}}
{{{30 = (2/3)(50) + b}}}
{{{-10/3 = b}}}
so, our final equation becomes
{{{y = (2/3)X - 10/3}}}