Question 260312
i have an isosceles triangle. One angle has 3x and the other angle has (x+50).
How to find the third angle.
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That depends on which of the two you listed is one of the equal angles.
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If 3x is paired with another 3x you get:
3x + 3x + x+50 = 180
7x = 130
x = 130/7
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3x = 390/7
x+50 = (130/7) + (350/7) = 480/7
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If (x+50) is paired with another (x+50) you get:
2(x+50) + 3x = 180
5x = 80
x = 16 degrees
3x = 48
x+50 = 66 degrees.
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Comment:
Judging from those answer I would guess the x+50
is one of the two equal angles.
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Cheers,
Stan H.