Question 260201
b+2=c
b=c-2
.
2a+1=c
2a=c-1
a=(c-1)/2
.
a^2+b^2=c^2
((c-1)/2)^2+(c-2)^2=c^2
(c^2-2c+1)/4 + c^2-4c+4=c^2
c^2-2c+1+4(c^2-4c+4)=4c^2
c^2-2c+1+4c^2-16c+16=4c^2
c^2-18c+17=0
(c-17)(c-1)=0
c=17
b=15
a=8
.
Ed