Question 260224
The tens digit of a two-digit number exceeds its units digit by 4. The number exceeds twice the number obtained by reversing the digits of the original number by 10. What is the original number? 
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Let the number be 10t+u
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Equations:
t = u +4
10t+u = 2(10u+t)+10
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Simplify the 2nd equation:
8t-19u = 10
t = u + 4
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Substitute for "t" and solve for "u":
8(u+4) - 19u = 10
-11u + 32 = 10
-11u = -22
u = 2
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Since t = u+4, t = 6
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Original Number: 10t+u = 62
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Cheers,
Stan H.