<PRE><B>Question 260218</B>
If I roll a standard 6-faced die three times, what is the probability that I roll at least one 6? Express your answer as a common fraction. 
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General rule: P(none) + P(at least one) = 1
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Your Problem:
P(no 6 in three rolls) = (5/6)^3
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P(at least one 6 in three rolls) = 1 - (5/6)^3 = 0.4213..
Cheers,
Stan H.</PRE>