Question 260232
Do you mean 
{{{1/2y-2=1/3y}}}
or 
{{{(1/2)y-2=(1/3)y}}}
I will assume 
(1/2)y-2=(1/3)y
{{{(1/2)y-2=(1/3)y}}}
multiply by 6
3y-12=2y
y-12=0
y=12