Question 259864
If I have a rose, a carnation, a tulip, and a daisy; how many different ways are possible if I have a blue vase, a green vase, and a white vase?

Since a rose - carnation in a blue is the same as a carnation - rose in a blue, would this be 4!3!?

Sol'n:
Your sol'n is correct:
N = 4!3! = 144 ways