Question 259977
Here's the basic outline to solving this problem.


1) First find the equation of the plane. To do this, compute the <a href="http://en.wikipedia.org/wiki/Cross_product">cross product</a> of u1 and u2 to find a third vector (say u3). This vector is the <a href="http://en.wikipedia.org/wiki/Surface_normal">normal</a> which will help you find the equation of the plane.


2) This normal will essentially be a line. So you can find the equation of that line using that normal vector and the vector (-7, -6, -2) (since you want the line to go through this point)


3) Use both the line and the plane to find the intersection between the two figures. This point will be closest to the given point (-7, -6, -2)



4) Finally, find the distance (using the distance formula) from the point found in step 3 and (-7, -6, -2) to find the distance from (-7, -6, -2) to the plane.



Let me know if this helps. If not, then repost or ask me.