Question 260106
write an equation of the line that is parallel to the given line and passes through the given point. 
Y=2/3X-2, (2,1) 
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The given line has a slope of 2/3.
Any line parallel to it must have a slope of 2/3.
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The form of the equation you want is y = mx + b
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You know m = 2/3 and you know y = 1 when x = 2:
So, solve for "b":
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1 = (2/3)*2 + b
1 = (4/3) + b
b = -1/3
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Equation:
y = (2/3)x - (1/3)
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Cheers,
Stan H.