Question 32709
x^2 = 4x + 12
=> x^2-4x-12=0
Based on quadratic formula, the roots of ax^2+bx+c = 0 are
[-b+sqrt(b^2-4ac)]/2a and [-b-sqrt(b^2-4ac)]/2a;
Here a = 1, b=-4, and c=-12
The roots are: [4+sqrt(16+48)]/2 and [4-sqrt(16+48)]/2;
=> The roots are 6 and -2;