Question 259971
Solve using quadratic formula. My book says the answer is {{{1+- sqrt (29)/(4)}}}
4x^2-2x-7=0
x={{{(-2+- sqrt(-2^2-4*4*-7))/(2*4)}}}
x={{{2+-sqrt(4+112)/(8)}}}
x={{{2+-sqrt(116)/(8)}}}
Note that we can factor to reveal a perfect square inside the radical
x={{{2+-sqrt(4*29)/(8)}}}
extract the perfect square
x={{{(2+-2*sqrt(29))/(8)}}}
You can cancel both 2's into the 8
x={{{1+-sqrt(29)/(4)}}}