Question 259881
The area of the triangle is given by:
{{{A = (1/2)(b*h)}}} but in an isosceles right triangle, b = h, so we'll just  say that b = x and h = x, so the area is:
{{{A = (1/2)x^2}}}
Now to find x, we'll use the Pythagorean theorem where c (the hypotenuse) = 15 ft.
{{{15^2 = x^2+x^2}}}
{{{225 = 2x^2}}} 
{{{x^2 = 112.5}}} Substitute into the equation for the area:
{{{A = (1/2)x^2}}}
{{{A = (1/2)(112.5)}}}
{{{highlight(A = 56.25)}}}sq.ft.