Question 259889
A jet leaves the Charlotte, North Carolina, airport traveling at an average rate of 564 km/h.
 Another plane leaves the airport one half hour later traveling at 744 km/h in the same direction.
 Use an equation to find how long the second jet will take to overtake the first.
:
:
Change 30 min to .5 hrs
:
Let t = time required for the faster jet catch up with the 1st jet
then
(t+.5) = travel time of the slower plane
:
When this happens, the two planes will have traveled the same distance.
:
Write a dist equation: dist = speed * time
Fast jet dist = slow jet dist
744t = 564(t+.5) 
744t = 564t + 282
744t - 564t = 282
180t = 282
t = {{{282/180}}}
t = 1.567 hrs or 1 + .567(60) = 1 hr 34 min