Question 259772
Find the value of k for which the equation 3x2 − kx + 7 = 0 will have two real solutions.

3x^2 -kx +7 = 0

a quadratic equation is ax^2+bx+c=0
solved by:
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
b^2-4ac is the discriminant
the discriminant needs to be greater than 0

a=3, b=-k, c=7
(-k)^2-4*3*7
k^2-12*7
k^2-84

k^2 needs to be greater than 84
k=sqrt(84)=sqrt(4*21)=2*sqrt(21)=9.165151
k needs to be greater than 9.165151