Question 259766
16x^2-6x+6=0
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The "discriminant" is the stuff under the radical in the quadratic equation:
b^2 - 4ac
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You could apply the above directly into your equation or you could have divided by 2 first.
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6^2 - 4(16)(6)
36 - 384
-348
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Since you have a "negative" -- the square root of a negative number would be imaginary.  Therefore, you can conclude that there are "no real solutions" for this quadratic.