Question 259596
Hello, 
Here's the way to solve this. 
X*3+6X*2+5X+30 Let's work on the first two:
X*3+6X*2 and rewrite this as: x^2(x+6)
Now let's work on the last two
5X+30 and rewrite this as:  5(x+6)
Notice we have in both parenthesis the same (x+6) so now we can rewrite the whole 
polynomial as:
(x^2+5)(x+6)=0  (I see the original didn't have it equal to zero but should be)
Now we can solve for x
x^2+5=0 Subtract 5 from both sides to give us:
x^2=-5 Sq rooting both sides gives us a negative sq rt so we know that's not right. 
x+6=0 Subtract 6 from both sides gives us:
x=-6 Plug this into the original equation and it works out. 
RJ 
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