Question 259515
Factor:
{{{8x^9+729y^3}}} First, do you recognise this as the sum of two cubes?
{{{(2x^3)^3+(9y)^3}}}
Recall that the sum of two cubes is factorable as:
{{{A^3+B^3 = (A+B)(A^2-AB+B^2)}}} and, here: {{{A = 2x^3}}} and {{{B = 9y}}}, so...
{{{8x^9+729y^3 = highlight((2x^3+9y)(4x^6-18x^3y+81y^2))}}}