Question 259569
Let x and x+2 be two consecutive odd integers. We get
{{{x(x+2) = 195}}}
and then
{{{x^2 + 2x = 195}}}
setting = 0 and factoring we get
{{{x^2 + 2x - 195 = 0}}}
{{{(x-13)(x+15)=0}}}
So,
x = 13 or
x = -15
--
Our two options are (13,15) and (-15,-13)