Question 259303
original equation is
{{{4x^2=12}}}
divide by 4 to get
{{{x^2 = 3}}}
take square root to get
{{{x = plus_or_minus sqrt(3)}}}
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x-intercept of f(x)=4x^2-12
let y =0 and solve for x.
we get the same as above
x = +- sqrt(3)