Question 4280
 If a^2x-3 * b^2x=a^6-x *b^5x prove that 3 log a =x log a/b 
  Apply log on both sides we have
 
 (2x-3) log a + 2x log b = (6-x) log a + 5x log b.
  (3x - 9) log a = 3x log b.
  3x (log a - log b) = 9 log a,
 So,  log a/b = 3 log a.  


 Note: as a good habit, you should group terms clearly as:
 a^(2x-3) * b^(2x)=a^(6-x) *b^(5x)

kENNY